Re: [libreoffice-users] To make a graph

At 17:05 28/08/2017 -0600, Jorge Rodríguez wrote:
> I have this set of data:
> U            A
> 1.37    13680
> 1.31    14000
>
> I've tried to graph these data that show two 
> lines, first 1.37 with 13680 and 1.31 with 14000, in the same graph.

Sorry, but this makes no sense. Each pair of 
value here defines a point, not a line. There are 
an infinity of lines that you can draw through 
any point, having all possible gradients.You need 
at least two points to define a line, and then 
only on the assumption that the line is straight.

> I want that the graph show where the lines intersect.

The infinity of possible lines through each of 
your two points intersect in a infinity of 
places. The question is not well enough defined 
to be answered. From your knowledge if the 
quantities that you are plotting, could you 
assume that both graphs go through the origin, 
(0,0)? If so, you could include these points and 
create two lines. But the answer to your query 
would then be trivial: the lines cross at (0,0)!

> And I prefer that A go in X axis and U in Y axis.

That's easy: just reverse the order of your 
columns of data. It is very easy to move or copy data.

> I couldn't do it yet. I put the data in some orders but I can get the graph.

That's because - with only one point in each set 
of data - there is no graph to get.

I trust this helps.

Brian Barker


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