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# Re: [libreoffice-users] Re: Generate a column of times

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On 2014-09-10 17:09, Brian Barker wrote:
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```At 16:58 10/09/2014 +1200, Steve Edmonds wrote:
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I think the trick is to not calculate the difference/no. samples and keep adding but to calculate the difference and multiply by position over number of samples added to start time.
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For the avoidance of doubt, you will see that this is what my original suggestion (two days ago) does.
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```For a quick test this seems to give times to 0.00 of a second ...
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No, it gives times to about *ten* fractional places of a second (0.0000000000), but it may well *display* with less precision - depending on your cell formatting. This is one of the original questioner's misunderstandings.
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Just meaning there is a pre-defined format that showed in my test to 0.00 seconds.
```Got to dash to beat the traffic, but can post the formula when I'm home.
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Or see my original reply: " In B2, enter: =B1+(B\$6-B\$1)/5 and fill this down to B5"!
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```Hi Brian.
What I am meaning would be
B2=B1+(B\$6-B\$1)*1//5
B3=B1+(B\$6-B\$1)*2/5
.
.
B5=B1+(B\$6-B\$1)*4/5

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Using =\$B\$1+(\$B\$6-\$B\$1)*(ROW(A3)-ROW(\$A\$1))/(ROW(\$A\$6)-ROW(\$A\$1)) makes the formula a bit more transferable.
```As you say you can use time format HH:MM:SS.00 or HH:MM:SS.000 as desired.

Steve

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