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Hi Eike,

Thanks for review!

Dnia 2011-08-06, sob o godzinie 17:35 +0200, Eike Rathke pisze:

             {
-                if ( aDelList[i] == nAddKey )
+                if ( *it == nAddKey )
                 {
                     bFound   = sal_True;
-                    nAt              = i;
+                    nAt              = it;
                 }
             }
             DBG_ASSERT( bFound, "Key not found" );
-            aDelList.Remove( nAt );
+            aDelList.erase( nAt );

Hmm.. I'd say the original code was wrong, when nAddKey was not found
in
aDelList it removed the first element anyway. That should be

               if (bFound)
                   aDelList.erase( nAt );

instead. 
There was so many questions that I forgot to ask. Should this code be
more changed? Because code in if(isRemoved_Impl()) is only entered if
there is nAddKey in aDelList. My question is why the key is double
searched? I think assertion will never be met.

Best Regards,
        Maciej


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