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On Fri, Sep 28, 2012 at 7:17 AM, Noel Grandin <noel@peralex.com> wrote:
That is exactly what makes it weird - it looks like a Java String, but it's
not, because you can do this:

    void f(OUString s) {
         s = "2";
    }

    OUString s = "1";
    f(s);
    cout << s; // will print "2"

ie. the modification inside the method is visible outside the method.

Really ? it does that ?
Whoaa, that is unexpected, and way wrong. That should be considered
'entrapment' :-/

Norbert

Context


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