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Thanks Tom

Dear Dave

It does work - you have to format the input  cells as stated.

b4 is formatted to Date, 31/Dec
c4 is text "to"
d4 is formatted to Date, 31/dec

then in

E4 =days360(b4,d4,3)

then input your 2 dates into b4 and d4     as in just type:-  01/07/2011 and
22/07/2011

and the answer in E4 is 21

you might want to add +1 to the E4 formula depending on if you decide the answer in E4 should be 22

I note that 1/7/2011 is the same as 01/07/2011, as is just 1/7 (as it auto inputs this year)

regards

John B

----------------------------------------------------------------------------------------------

On 22/07/2011 20:41, Tom Davies wrote:
Hi :)
I think John's answer was mostly so you could copy&paste into the right places!


To do the formatting in the first part of his answer click on the cell and then
look up at the menus at the top of the LibreOffice window.  The menus should be
something like

File  ..  View ... Edit ... (err i can't remember) ... Format ... (more i can't
remember) ... Window ... Help
So, click on the "Format" menu, choose  "Cell" and a pop-up box should appear
with lots of "tabs" at the top.  Choose the first one, "General" (or
something).  Somewhere on the left should be an option for "Date" which then
gives you various sub-options.

Hope this helps but there is a guide with screen-shots somewhere that might help
so don't worry if it's not obvious.  See Chapter 5

http://www.libreoffice.org/get-help/documentation/
Regards from
Tom :)




________________________________
From: Dave Douglas<ddouglas1@farmersagent.com>
To: users@global.libreoffice.org
Sent: Fri, 22 July, 2011 20:06:33
Subject: Re: [libreoffice-users] Compute difference

Thanks, but I am not a programmer.  I have troubles being understood in
English.  Is there a way of doing it through the menus?

Feeling unworthy,
Dave


-----Original Message----- From: John B
Sent: Friday, July 22, 2011 12:00 PM
To: users@global.libreoffice.org
Subject: Re: [libreoffice-users] Compute difference

Try this

b4 is formatted to Date, 31/Dec
c4 is text "to"
d4 is formatted to Date, 31/dec

E4 = ((-B4+D4)/7 +(1/7)

f4= Trunc(e4)

g4= (+e4-F4)*7


then type in your 2 dates into b4 and d4     as in  01/07/2011 and
22/07/2011


regards

John B

--------------------------------------------------------------------------------





On 22/07/2011 15:15, Jérôme Fenal wrote:
Hi all,

I need to do a difference in days between two dates, _without_ taking into
account leap years (e.g. considering all years are 365 days long).

The right way to do that would be to use function
DAYS360(date1;date2;method) using method = 3 as in other financial
functions, but it does seems to be implemented (only 0&   non 0 are
meaningful for this function currently).

Does anybody know how to still do this without ressorting to a procedural
language ?

Regards,

J.

PS: I'll be digging into BZ to see if there is already a request for such an
enhancement to DAYS360().




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