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On 8 Jun 2011 at 10:37, Stephan Zietsman wrote:

Date sent:              Wed, 8 Jun 2011 10:37:07 +0200
Subject:                Re: [libreoffice-users] Re: Calc: Has anyone 
tested the
        backward-compatibility of LibreOffice 3.4?
From:                   Stephan Zietsman <sziets@gmail.com>
To:                     users@libreoffice.org
Send reply to:          users@libreoffice.org

Stephan wrote:
 To get a more user friendly result, use the following formula:

= IF(MIN(ISNUMBER(G4:H7)), "All values are numeric",
ADDRESS(MIN(IF(ISNUMBER($G$4:$H$7), "All good", ROW($G$4:$H$7))),
MIN(IF(ISNUMBER(OFFSET($G$4:$H$7,MIN(IF(ISNUMBER($G$4:$H$7), "All
good", ROW($G$4:$H$7))) - MIN(ROW($G$4:$H$7)), 0, 1)), "All good",
COLUMN(OFFSET($G$4:$H$7,MIN(IF(ISNUMBER($G$4:$H$7), "All good",
ROW($G$4:$H$7))) - MIN(ROW($G$4:$H$7)), 0, 1))))))

I just have a small correction to make.  For consistency, the first
range reference in the formula should also be absolute (i.e. G4:H7
should be $G$4:$H$7).  So the formula should actually be:

= IF(MIN(ISNUMBER($G$4:$H$7)), "All values are numeric",
ADDRESS(MIN(IF(ISNUMBER($G$4:$H$7), "All good", ROW($G$4:$H$7))),
MIN(IF(ISNUMBER(OFFSET($G$4:$H$7,MIN(IF(ISNUMBER($G$4:$H$7), "All
good", ROW($G$4:$H$7))) - MIN(ROW($G$4:$H$7)), 0, 1)), "All good",
COLUMN(OFFSET($G$4:$H$7,MIN(IF(ISNUMBER($G$4:$H$7), "All good",
ROW($G$4:$H$7))) - MIN(ROW($G$4:$H$7)), 0, 1))))))

Once again, remember to enter it as an array formula (by pressing
CTRL+SHIFT+ENTER instead of just ENTER).

The Address function was something I didn't recall, use to teach a 
spreadsheet class, but haven't in a long time. Did come up with 
some other testing.

Filled in A1:AF20 with a bunch of numbers, and then I randomly 
put in some "a" characters in cells.

In Cell AG1 placed this to get the number of non-numeric
=COUNTA(A1:AF20)-COUNT(A1:AF20)

In Cells AH1 thru AH15 put the numbers 1 to 15

In Cell AI1 thru AI15 put this formula
{= SMALL((IF(ISNUMBER($A$1:$AF$20), "ALL 
GOOD",COLUMN($A$1:$AF$20)*1000+ROW($A$1:$AF$20))), 
AH1)}

Then in AJ1 thru AJ15 put this formula
=ADDRESS(MOD(AI1,1000),INT(AI1/1000))

This is the result. 
13 non-numeric fields and their addresses.

                                                                  13
                                                                   1
                                                                1007
  $A$7


                                                                   2
                                                                4011
  $D$11


                                                                   3
                                                                8010
  $H$10


                                                                   4
                                                               11012
  $K$12


                                                                   5
                                                               13007
  $M$7


                                                                   6
                                                            17011   
  $Q$11


                                                                   7
                                                               19015
  $S$15


                                                                   8
                                                               24017
  $X$17


                                                                   9
                                                               26009
  $Z$9


                                                                  10
                                                               29009
  $AC$9


                                                                  11
                                                               31015
  $AE$15


                                                                  12
                                                               32011
  $AF$11


                                                                  13
                                                               32015
  $AF$15


                                                                  14
                                                             #VALUE!
                                                             #VALUE!
                                                                    

                                                                  15
                                                             #VALUE!
                                                             #VALUE!
                                                                    

Could add an if to the AJ formula to only display if less than or 
equal to $AG$1.




Regards
Stephan

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