Re: [libreoffice-users] Help with find & replace.

Den ons 16 mars 2022 kl 21:44 skrev Dave Barton <daveb@libreoffice.org>:

> On 16/03/2022 20:01, Steve Edmonds wrote:
> > On 17/03/2022 08:34, Dave Barton wrote:
> > > On 16/03/2022 18:27, Brian Barker wrote:
> > > > At 16:29 16/03/2022 +0000, Dave Barton wrote:
> > > > > I am looking for a find & replace solution in Writer, where there is a
> > > > > blank space as the last character of a paragraph (eg. last word
> > > > > <space><LF><CR>). In the original OOo and most of the text editors I
> > > > > use the simple solution that worked/works perfectly is: Find =
> > > > > <space>$ Replace = $ (Note: I use <space> here to represent a single
> > > > > space character). This does not work in LO Writer, so I am forced to
> > > > > fiddle around copying from LO and pasting into AOO, running F&R in
> > > > > AOO, then copy/paste back again. Any pointers would be welcome.
> > > > I'm surprised that exactly what you say works in OpenOffice. Don't you
> > > > need to find space-dollar, just as you describe, but to replace with
> > > > nothing? Replacing with dollar will surely insert an unwanted dollar
> > > > character?
> > > >
> > > > Or have you forgotten to click "Other options" in the Find and Replace
> > > > dialogue and to tick "Regular expressions"?
> > > >
> > > > I trust this helps.
> > > >
> > > > Brian Barker
> > > Hi Brian,
> > >
> > > After 22 Years of you and I being involved in this project, I genuinely
> > > bow to your superior knowledge in this area. However, I do assure you
> > > that the convoluted LO->AOO->LO  nonsense works for me, exactly as it
> > > did in the days of OOo.
> > >
> > > No, I have not forgotten to click "Other options in the Find and Replace
> > > dialogue and to tick "Regular expressions", please see my screen
> capture:
> > > https://www.mediafire.com/view/80552jkp3qw6o8x/F%2526R_LO.png/file
> > >
> > > Here is a very simplistic file illustrating the <space><CR><LF>
> > > paragraph endings:
> > > https://www.mediafire.com/file/vmixa9r4dhjpc9e/F%2526R_LO.odt/file
> > >
> > > Version: 7.3.1.3 (x64) / LibreOffice Community
> > > Build ID: a69ca51ded25f3eefd52d7bf9a5fad8c90b87951
> > > CPU threads: 8; OS: Windows 10.0 Build 19043; UI render: default; VCL:
> > > win
> > > Locale: es-ES (en_IE); UI: en-US
> > > Calc: threaded
> > >
> > > If you can please show me where I am going wrong, I would be extremely
> > > grateful.
> > >
> > > Dave Barton
> > May be this is sorted and I have received the emails out of order, but
> > assuming you just want to remove the trailing space from each line, both
> > Johnny's and Michael's methods work for me on your sample file.
> >
> > Find= [:space:]{1,}$
> > Replace= empty
> >
> > Find= <space>$
> > Replace= empty
> >
> > Use regular expression= checked
> > Steve
>
>
> Thanks Steve, but no it's NOT sorted.
>
> You have "Kinda" given me 1/2 a clue.
>
> What does {.1.} mean?

It means ”one or more of the previous character”. Well, it's {1,}, not
{.1.}.
You can also specify a maximum value, like this: {1,5}. This means ”at
least one and not more than 5 of the previous character.
For instance:
[0-9]{3,5}
This means at least three and not more than 5 numerical characters.


Kind regards

Johnny Rosenberg


> In all my researching of regular expressions, I have never encountered
> this option. The wonderful thing about *_STANDARDS_* is that there are
> such a wide variety of different ones to randomly chose and use.
>
> Dave
>
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