Re: Fwd: [libreoffice-users] macro to only change month

Just for fun, here's a workaround for the DateSerial issue in LibreOffice
Basic (the fact that things like DateSerial(2018,13,59) isn't allowed. I am
at work so I could only test this in Excel (in which the function isn't
needed anyway), but it should work in LibreOffice Calc as well:

REM ***** BASIC *****
Option Explicit

Public Function MyDateSerial(lYear As Long, lMonth As Long, lDay As Long)
As Date
    lYear = lYear + Int((lMonth - 1) / 12)
    lMonth = 1 + (lMonth - 1) Mod 12
    MyDateSerial = DateSerial(lYear, lMonth, 1) + lDay - 1
End Function
REM ***** END BASIC *****

Then use MyDateSerial instead of DateSerial, and you don't need to verify
month and date values, it will work as in Excel, but maybe a bit slower.
Hopefully not too slow, though.

Test (in Excel):

Debug.Print MyDateSerial(2018, 13, 59)
2019-02-28

Debug.Print MyDateSerial(2018, 14, 59)
2019-03-31

Debug.Print MyDateSerial(2019, 14, 59)
2020-03-30

The result of last example is of course expected, since 2020 is a leap year.

Thanks to the ",1) + lDay - 1" at the last line in the function, we get
away with it without having to check how many days each month has, which
makes the function look short and not so messy.


A little bit off topic, but since I mentioned it as a possible "bug" I
thought it would be appropriate to suggest a workaround for it. :)


Kind regards

Johnny Rosenberg


2018-01-28 12:40 GMT+01:00 Johnny Rosenberg <gurus.knugum@gmail.com>:

> 2018-01-28 9:04 GMT+01:00 Brian Barker <b.m.barker@btinternet.com>:
>
> > At 08:52 28/01/2018 +0100, Johnny Rosenberg wrote:
> >
> > > For some strange reason you need to make sure you enter valid values for
> > > month and day. In Excel (which sucks in most aspects, but I have to use it
> > > at work) you can do things like DateSerial(2017, 13, 59), which returns the
> > > date value for 2018-02-28, but that seems to throw an error in LibreOffice.
> > > That's odd, or at least primitive, I think. It would be very convenient not
> > > having to think about those boundaries, just increase the month number and
> > > it just works. Maybe I should file a bug report or enhancement request
> > > about that…
> >
> > Does =DATE(2017;13;59) not give 2018-02-28 for you?
>
> Yes, it does. I was referring to the Basic function DateSerial:
>
> Sub Main
>     Print DateSerial(2017,13,59) ' Gives error message.
> End Sub
>
>
> > Brian Barker
> >
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