Re: [libreoffice-users] Issue with INDEX function

Gregory Smith - Oracle Sparc Verification wrote:
> AllI have created a one dimensional array called CATEGORY.When I do this function: 
> =Index(Category,25,0)I get the contents
>        of that index - lets say it is the word "cats"When I do this function 
> =if((index(category,25,0)="cats"),1,0)I
>        get FALSE?!!Anyone have any ideas what I am doing wrong?gs

With that formula, you should get 0 if the strings don't match (or 1 if 
they do); do you really get FALSE displayed in the cell?

Assuming you actually get 0 (because the condition 
(index(category,25,0)="cats") is evaluating to FALSE), make sure there 
are no spaces in the values. "cats " is not equal to "cats", even though 
they look the same. If spurious spaces are likely to be a problem, you 
may want to use:
  =if((trim(index(category,25,0))="cats"),1,0)
to remove spaces either side of the value (and collapse multiple spaces 
within the value into single spaces) before comparison.

Mark.

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