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# [libreoffice-users] Re: calc - hours of work in a month

```On 05.06.2013 19:48, Brian Barker wrote:
```
```At 19:39 05/06/2013 +0200, Adam Noname wrote:
```
```On 05.06.2013 19:19, Brian Barker wrote:
```
```At 18:43 05/06/2013 +0200, Adam Noname wrote:
```
```I have two list of times in format HH:MM , :
[...]
Then I want to sum all differences. It is not hard = SUM(D2:D33) .
It should be in [HH]:MM format to show good number of hours. My
result is: 149:43 .  I want to round it to full hours, which should
be IMHO 150 .  How can I do it ?
```
```
The underlying value for your total is a simple numeric value, so the
fact that your fraction of an hour is shown in base 60 (as minutes)
is no complication.  This underlying value is in days, so you need to
multiply by 24 to get hours and then to round that:
=ROUND(Xn*24)
```
```
= ROUND(SUM(D2:D33)*24)

but I get : 3600:00 .  I have also to change cell format to number and
then it works as expected  150
```
```
Indeed - because it is a number, of course!

Brian Barker

```
```One must be carefull with 24:00 and 00:00 hours
Maybe [HH]:MM format is safer in this case

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