Hi Jean,
Thanks for help !
Finally, I did : *aRealStyle.copy(0,(aRealStyle.Search(aSep) + aSep.Len()));
*
It also worked :)
Thanks once again!
-Prashant
On Sun, Feb 17, 2013 at 11:11 PM, Jean-Noël Rouvignac <
jn.rouvignac@gmail.com> wrote:
Hi Prashant,
2013/2/17 Prashant Pandey <prashant3.yishu@gmail.com>
Hi,
I need some guidance as am stuck at a place.
How should I replace 'erase' using guidelines given under
https://wiki.documentfoundation.org/Development/String_Classes.
If I try to fit 'replaceAt' in place of 'erase' in the line bolded below:
* aRealStyle.Erase(aRealStyle.Search(aSep) + aSep.Len());*
it will give me error (if I do : *aRealStyle.replaceAt(aRealStyle.indexOf(aSep)
+ aSep.getLength());*)
Reason:
replaceAt defined as: rtl::OUString rtl::OUString::replaceAt(sal_Int32,
sal_Int32, const rtl::OUString&) const
(candidate expects 3 arguments, 1 provided)
error: no matching function for call to
‘rtl::OUString::replaceAt(sal_Int32)
My question is, what should I pass inside the replaceAt()
parameters/arguments?
I would suggest you write this:
* sal_int32 idx = **aRealStyle.indexOf(aSep) + aSep.getLength();*
* **aRealStyle = aRealStyle.replaceAt(idx, **aRealStyle.getLength() - *
*aRealStyle, "");*
Because:
- If nIndex is set then can use replaceAt with an arg of an empty
string (from the wiki page)
- The second argument is the count, and here we replace until the end
of the string
- Since OUString is immutable, you must assign back the resulting
OUString if you do not want to lose it
Cheers,
Jean-Noël
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