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Hi Jean,

Thanks for help !

Finally, I did : *aRealStyle.copy(0,(aRealStyle.Search(aSep) + aSep.Len()));
*

It also worked :)

Thanks once again!

-Prashant

On Sun, Feb 17, 2013 at 11:11 PM, Jean-Noël Rouvignac <
jn.rouvignac@gmail.com> wrote:

Hi Prashant,

2013/2/17 Prashant Pandey <prashant3.yishu@gmail.com>

Hi,


I need some guidance as am stuck at a place.
How should I replace 'erase' using guidelines given under
https://wiki.documentfoundation.org/Development/String_Classes.
If I try to fit 'replaceAt' in place of 'erase' in the line bolded below:

*            aRealStyle.Erase(aRealStyle.Search(aSep) + aSep.Len());*

it will give me error (if I do : *aRealStyle.replaceAt(aRealStyle.indexOf(aSep)
+ aSep.getLength());*)

Reason:

replaceAt defined as: rtl::OUString rtl::OUString::replaceAt(sal_Int32,
sal_Int32, const rtl::OUString&) const
(candidate expects 3 arguments, 1 provided)
error: no matching function for call to
‘rtl::OUString::replaceAt(sal_Int32)

My question is, what should I pass inside the replaceAt()
parameters/arguments?


I would suggest you write this:
*    sal_int32 idx = **aRealStyle.indexOf(aSep) + aSep.getLength();*
*    **aRealStyle = aRealStyle.replaceAt(idx, **aRealStyle.getLength() - *
*aRealStyle, "");*

Because:

   - If nIndex is set then can use replaceAt with an arg of an empty
   string (from the wiki page)
   - The second argument is the count, and here we replace until the end
   of the string
   - Since OUString is immutable, you must assign back the resulting
   OUString if you do not want to lose it

Cheers,

Jean-Noël


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