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[libreoffice-users] Re: Basic Macro – Copy array of custom type


Den sön 14 apr. 2019 kl 21:53 skrev Johnny Rosenberg <gurus.knugum@gmail.com
>:

> Hi!
> As we know by now, in LibreOffice Basic we can not copy an array directly,
> we will only get a new name for the same array. It's like assigning two
> array pointers to the same array. The obvious way to copy an array is to do
> it element by element in a loop, but there is a workaround. Here's an
> example that works:
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> *Option ExplicitSub Test1 Dim A(9) As Long Dim i As Integer'
> Initialise a: For i=0 To 9 A(i)=i Next i' Copy A to B:
> Dim B(9) As Long: B=A ReDim Preserve B(9)' Do some changes to B
> without affecting A: B(7)=A(3) B(3)=A(7)*
> *' Display the results:*
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> * Dim Message As String, Tab As String, NL As String, Spc As String
> Tab=Chr(9): NL=Chr(13): Spc=" " Message="i" & Tab & "A(i)" & Tab &
> "B(i)" & NL For i=0 To 9 Message=Message & i & Tab & Spc & A(i) &
> Tab & Spc & B(i) & NL Next i MsgBox MessageEnd Sub*
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> So, the trick in this case is to first assign B to A, then running the
> ReDim statement. After that we have two separate arrays.
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> However, I want to do this with a custom type, like so:
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> *Private Type NumberType Value As Long Status As BooleanEnd
> Type*
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> *Sub Test2 Dim A(9) As NumberType Dim i As Integer' Initialise
> a. For i=0 To 9 A(i).Value=i A(i).Status=True Next
> i' Copy A to B Dim B(9) As NumberType: B=A ' ”Basic runtime error:
> Object required.” ReDim Preserve B(9)End Sub*
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> This will throw a runtime error at *B=A* at third line from the end:
> ”Basic runtime error: Object required”. What am I missing? How to do this
> properly?
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> Kind regards
>
> Johnny Rosenberg
>
>
OK, to get rid of the error the keyword ”Let” was required. So finally I
know what that's for…
This code doesn't give me any errors, but the results are not right:

*Option Explicit*



*Private Type NumberType Value As Long Status As BooleanEnd Type*

































*Private Sub Test2 Randomize Dim A(9) As NumberType Dim i As
Integer' Initialise a. For i=0 To 9 A(i).Value=i
A(i).Status=True Next i' Copy A to B Dim B(9) As New NumberType:
Let B=A ReDim Preserve B(9)' Do some changes to B without affecting
A: B(7).Value=A(3).Value B(3).Value=A(7).Value
B(3).Status=False B(7).Status=False Dim Message As String, Tab As
String, NL As String: Tab=Chr(9): NL=Chr(13) Dim Spc1 As String, Spc2 As
String: Spc1=" ": Spc2=" " Message="i" & Tab & "A(i)" & Tab & Tab & Tab
& "B(i)" & NL For i=0 To 9 Message=Message & i & Tab & Spc2 &
_ A(i).Value & Spc1 & _ A(i).Status & Tab &
Tab & Spc2 & _ B(i).Value & Spc1 & _
B(i).Status & NL Next i MsgBox MessageEnd Sub*

It seems like ReDim Preserve has no effect in this case. A and B are still
pointers to the same array, as it seems.
Suggestions? Except assigning all the values in loops, because I already
know that…


Kind regards

Johnny Rosenberg

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[libreoffice-users] Basic Macro – Copy array of custom typeJohnny Rosenberg <gurus.knugum@gmail.com>
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