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Awesome, thanks!

I replicated that, and now I can just name the columns and the delete the
preceding columns with the variable names and I am in business.

One of these babies is 11775 rows ;-)



On Sun, Mar 13, 2022 at 9:18 AM Michael D. Setzer II <msetzerii@gmail.com>
wrote:

Loaded the csv file with libreoffice and click on space and
other boxes and entered :.
That brings in columns A thru AB.


On 13 Mar 2022 at 9:05, Rogier F. van Vlissingen wrote:

From:                   "Rogier F. van Vlissingen"
<vliscony@gmail.com>
Date sent:              Sun, 13 Mar 2022 09:05:56 -0400
Subject:                Re: [libreoffice-users] Spreadsheet
question
To:                     David Lynch <dlynch1319ng@gmail.com>
Copies to:              users@global.libreoffice.org

wow... I had never used that function before...

I am not quite there yet, however, but at least this is a path. Here
is an
example of one of the strings

Date:20220302 Time:1631 PM1.0:000 PM2.5:000 PM10:000 CO2:0010
HCHO:0.001
TVOC:0.000 >0.3DustNum:00000 >0.5DustNum:00000 >1.0DustNum:00000
2.5DustNum:00000 >5.0DustNum:00000 >10DustNum:00000

Using the expression as you wrote it, I get fields, like this:
Date 20220302 Time 1631 PM1.0 000 PM2.5 000 PM10 000 CO2 0010 HCHO
0.001
TVOC 0.000 >0.3DustNum 00000 >0.5DustNum 00000 >1.0DustNum 00000
2.5DustNum 00000 >5.0DustNum 00000 >10DustNum 00000 and then I could
name the columns and delete the columns with the variable names.

I will have to study that function... thanks.




On Sun, Mar 13, 2022 at 8:41 AM David Lynch <dlynch1319ng@gmail.com>
wrote:

On 13/03/2022 12:04, Rogier F. van Vlissingen wrote:
Var1: value1 Var2: value2 Var3: value 3 ... Var10: value10

Place the strings in column 1 than put

=REGEX($A1,"(?<=^| |:)[^ ]+?(?=:| |$)",,COLUMN()-1)

in column 2 and drag right for ten columns and down.

David Lynch



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+------------------------------------------------------------+
 Michael D. Setzer II - Computer Science Instructor
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