Then use >0.0000001 or whatever value works instead of >0
On 29 Jan 2021 at 14:06, James wrote:
Subject: Re: [libreoffice-users] calc: index column A with
column B
To: Rob Jasper <Rob@famjasper.nl>
Copies to: users@global.libreoffice.org
From: James <bjlockie@lockie.ca>
Date sent: Fri, 29 Jan 2021 14:06:08 -0500
Another problem.
Some of the numbers display as 0 but are calculated so have fractions like
0.0000000812344372353
I want to find the last row that displays as non-zero.
On 2021-01-29 6:30 a.m., Rob Jasper wrote
James,
Since a MINIF function does not exist you can use MINIFS.
Change MIN(B:B) to MINIFS(B:B;B:B;">0")
Success,
Rob
Op 29 jan. 2021, om 03:59 heeft James <bjlockie@lockie.ca> het volgende geschreven:
I want to find the row in column A that corresponds to the row of a
value in column B.
eg.
row A B
1 10 220000
2 20 150000
3 30 3000
4 40 10
=some_function('A',minimum_function(B));
where minimum_function(B) returns 4 and some_function('A',4) returns the
value in column A at row 4.
I asked the previous and someone gave me the formula:
=INDIRECT("$A"&MATCH(MIN(B:B);B:B;0))
It worked fine but now I have some rows with zeros (more than one row):
row A B
1 10 220000
2 20 150000
3 30 3000
4 40 10
5 50 0
6 60 0
Is there a MINBUTGREATERTHANZERO function?
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