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# Re: [libreoffice-users] Calc: Calculate number of days until yesterday IE TODAY-1 to assist in array determination for COUNTIF?

```On 28-4-2018 09:14, Luuk wrote:
```
```On 27-4-2018 18:04, Hylton Conacher (ZR1HPC) wrote:
```
```Hi,

I am running LibreOffice 5.4.6.2 and am using a spreadsheet to enable
me to draw graphs based on rainfall received per year, up until the
date prior to today. The figures also allow me to compare current
rainfall to date to the same period in a previous year. I agree I
should probably use Base but I do not think it would have solved the
issue.

**Example Data***,,,,,
Month,Day,M/D,2016,2017,2018,Average('16->'17)
Apr,1.04/01,3,0,1,1.5
Apr,2,04/02,0,8,0,4
,,,,,,
,,,,,,
,,,,,,
Apr,26,04/26,0,0,20,0

Assuming today is Apr 2nd, a formula to count how many days of rain
there were in the current month would be =COUNTIF(\$F\$2:\$F2,">0"). The
Total amount of rain that fell on that number of days, being 1, was
1mm, or taking it further 60% of the average rainfall to date for the
month.

Assuming today is Apr 27, a formula to count how many days of rain
there were in the current month is unknown, especially as there are
undoubtedly values in the other un-shown 81 cells i.e. 3yrs and 27
remaining days?

Basically take the starting cell reference \$F\$2 and add the number of
events that were ">0" to get the end reference for the COUNTIF formula.

=COUNTIF(\$F\$2:Add number of items ">0" to the starting line reference
2, to get the end of the COUNTIF range) i.e. being Apr 27, whilst
there may be 26 days between the beginning of Apr and today i.e.
Today()-1, there are only two instances in the above table where ">0"
for a particular year, thus making 2 the number of days it rained, to
receive the SUM of the 2018 rainfall being 21mm

I have Googled silly but my GFu is lacking something as the solution

For reference the formula to count the number of days from 1st Apr to
Yesterday:
=DAYS(TODAY(),"2018-04-01")

I have uploaded the file to

I will need to re-write at least 36 formulae being one for each month
of three years, but then hopefully I can leave column AC and
concentrate on entering the data correctly and optimising the graphs.

Ideally I think I need a formula to give me the number of days between
\$F\$2 and 'TODAY() -1' and add that number to the cell reference to
create the end of the COUNTIF range.

I hope you can point me in a direction that will help.

Regards
Hylton

```
```This can be solved using the INDIRECT function

Example
A1: 1
B1: 2
C1: 3
D1: "A1:C1"
E1: =AVERAGE(INDIRECT(D1))

This will result in E1 showing the average value of cells A1:C1

```
```or, another example

if you change B374 to: 01-01-2016
and B375 to: EOMONTH(B374;0)+1
and copy B375 to B376:B385, and change Format cell to 'MMM'

C374: ="D3:D"&(2+A374)
C375:
="D"&DAYS(3+EOMONTH(B374;0)+1;"01-01-2016")&":D"&DAYS(3+EOMONTH(B375;0)+1;"01-01-2016")
copy C375 to C376:C385

change D374 from '=SUM(D\$3:D\$33)' to '=SUM(INDIRECT(B374))'
copy D374 to D375:D385

Then values in your sheet should look like this (range A374:D386):
31      jan     *D3:D33*        1
28      feb     D34:D63         0
31      mrt     D63:D94         59
30      apr     D94:D124        44
31      mei     D124:D155       19
30      jun     D155:D185       137
31      jul     D185:D216       151
31      aug     D216:D247       83
30      sep     D247:D277       51
31      okt     D277:D308       15
30      nov     D308:D338       3
31      dec     D338:D369       44
365     *Total*
607

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