Hi Brian
I wish i could say it did help but unfortunately not. It works with the whole cell contents but
doesnt seem to pick out a word within the cell. For instance, one of my list has contents "X1 G43".
Now if I have "X1 G43" in the cell Xn (using your example) i get count 1 returned which is correct;
but if i have "X1" in cell Xn it returns 0, which is clearly wrong (at least as far as my
requirements are concerned). And yes, i do have regular expressions enabled in Calc > Calculate.
My version is 5.2.2.2 x64 and im using 64bit windows 7.
G.
--------------------------------------------
On Sun, 12/3/17, Brian Barker <b.m.barker@btinternet.com> wrote:
Subject: Re: [libreoffice-users] regular expression for calc
To: users@global.libreoffice.org
Date: Sunday, 12 March, 2017, 5:51
At 15:45 11/03/2017 +0000, Gary
Collins wrote:
I have a column each row of which contains a sequence of
one or more
codes separated by a space. In case it will make a
difference each
code consists of a letter (occasionally 2 letters)
followed by a
number of up to 3 digits (and occasionally ends with a
letter) eg X1
Aa12 D7a etc.
I want to obtain a regular expression for COUNTIF that
will enable
me to find out how many times a particular code,
contained in
another cell, occurs in the column. I was thinking that
\b to detect
the word boundaries should help but i cant quite get it
to work; im
not sure if this is because it is assuming a word
boundary between
the letter and the number or if it is simply my
incompetence as
usual. Does anyone have an idea what may be the best way
to achieve this?
Try
=COUNTIF(range;"\b"&Xn&"\b")
- where "range" represents the column of data and Xn
represents the
cell containing the code to be counted. Remember that you
need to
have Tools | Options... | LibreOffice Calc | Calculate |
Enable
regular expressions in formulae ticked (which is the case by
default).
I trust this helps.
Brian Barker
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- Re: [libreoffice-users] regular expression for calc · Gary Collins
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