Thank you very much Brian.
Have a nice evening,
Carlo
ing. Carlo Strata
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via Botticelli 1/4
30031 Dolo - VE
Italia - Italy
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tel. +39.041.822.0665
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Skype carlo.strata
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Il 01/12/2014 14:58, Brian Barker ha scritto:
At 14:04 01/12/2014 +0100, Carlo Strata wrote:
I suppose (!) there is an addition to the two behaviors ("Err:511"
and "#N/A", respectively from LO and Excel) described by Luuk: Excel
evaluate only the part it calculate and not the entire formula or
lose the internal "#N/A" in calculations. I cannot check this because
I have not Excel anymore on my notebook...
In other words, if you use a formula like this:
=IF(1=1;3;LOOKUP(;"peace"))
LO check the entire formula and answer "Err:511" and Excel? Someone
may check for this?
Excel needs comma separators instead of semi-colons, of course - but
the equivalent formula yields 3 in Excel 2010. If you change the test
to 1<>1 to force it to evaluate the LOOKUP(), it gives a #VALUE! error
because "peace" is a text value, not an array. If you substitute an
array here, it gives #N/A. In either of these latter cases, if you ask
it to show calculation steps, it has evaluated the inequality to
FALSE, identified the LOOKUP as the next thing to evaluate, and says
"The next evaluation will result in an error."
Brian Barker
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Context
- Re: [libreoffice-users] [Calc] The LOOKUP() function (Calc vs. Excel) (continued)
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