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Of course! I don't think binary!


On Wed, 13 Aug 2014 09:42:12 +0100
Brian Barker <> wrote:

At 15:55 13/08/2014 +1000, Keith Bates wrote:
While I agree with most of your post, a slight typo or something 
crept in here, where you confuse 10^53 with 2^53

2^53 is one followed by fifty-three zeroes, of course - so is just 
too long to be stored accurately.

I wasn't clear - but not in the way you thought! I meant that 2^53 is 
represented *in binary* (as it will be in the computer) as one 
followed by fifty-three zeroes, of course. So it's the value that is 
just too large to be stored accurately in double precision. (As so 
often happens, I spotted that omission just after I had sent the

Brian Barker  

God bless you
Keith Bates

Jesus is the Way,
the Truth and the Life.
Follow Him.

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