On 05/25/2013 07:10 AM, Ian Whitfield wrote:
Thanks Noel !!!
On 25/05/13 11:58, Marion & Noel Lodge wrote:
Assuming your field is 'Country', try this -
SELECT Country, Count(Country) AS 'Count'
FROM <your Table name>
GROUP BY Country
ORDER BY Country
I had a problem, at first - as I always seem to do - with 'Syntax
Error'!! So I created it with the Wizard and edited it in SQL view.
This resulted in ...
SELECT `Members`.`Country` AS `Country`
FROM `FedSaintsNew`.`Members` `Members`
GROUP BY `Members`.`Country`
ORDER BY `Members`.`Country`
This worked 100%!! So thanks very much. It does bring up two 'Blank'
results, (which I guess must have a space in them or something). I
don't know how to track these down but it's not too important.
Appreciate the help.
IanW
Pretoria RSA
If all you want is a count of the distinct countries in your
table, try this:
SELECT COUNT( DISTINCT `Members`.`Country`) AS `Country`
FROM `FedSaintsNew`.`Members` `Members`
--Dan
--
To unsubscribe e-mail to: users+unsubscribe@global.libreoffice.org
Problems? http://www.libreoffice.org/get-help/mailing-lists/how-to-unsubscribe/
Posting guidelines + more: http://wiki.documentfoundation.org/Netiquette
List archive: http://listarchives.libreoffice.org/global/users/
All messages sent to this list will be publicly archived and cannot be deleted
Context
Privacy Policy |
Impressum (Legal Info) |
Copyright information: Unless otherwise specified, all text and images
on this website are licensed under the
Creative Commons Attribution-Share Alike 3.0 License.
This does not include the source code of LibreOffice, which is
licensed under the Mozilla Public License (
MPLv2).
"LibreOffice" and "The Document Foundation" are
registered trademarks of their corresponding registered owners or are
in actual use as trademarks in one or more countries. Their respective
logos and icons are also subject to international copyright laws. Use
thereof is explained in our
trademark policy.