Re: [libreoffice-users] If Cell Contains String True

On Thu, Feb 21, 2013 at 1:43 PM, Joel Madero <jmadero.dev@gmail.com> wrote:

> What I have:
>
> A|B
> comment|regression check
> regression|
> regression,BSA,i10n|
> BLANK|
> BLANK|
> regression|
> regression,bibisected|
> BSA|
> BSA|
> cleanup0407|
>
> If that's not clear those are A1:B10, where | splits A and B columns. B
> column is empty other than B1 which has header "regression check"
>
> I need a formula which will be true if the word "regression" is in A at all
> (so in the above example A2, A3,A5,A6 would all be true).

If I'm understanding what you want I think this function will give the
results you're looking for
 =NOT(ISERROR( SEARCH("regression",A2)))

SEARCH() is case insensitive so finds the word no matter the capitalization
ISERROR() accounts for empty cells and cells with numbers that cause
SEARCH() to fail
NOT() causes the result to be TRUE when ISERROR() returns FALSE because the
nested SEARCH() is TRUE

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