Den 23.01.2013 14:32, skreiv Brian Barker:
Thanks. I think this will help me out. Although I would have preferred a
simpler version :-)
At 13:44 23/01/2013 +0100, Kolbjørn Stuestøl wrote:
Den 23.01.2013 07:29, skreiv Brian Barker:
At 22:57 22/01/2013 +0100, Kolbjørn Stuestøl wrote:
Is there any way to find the first occurrence of a number less (or
greater) than a given number in an unsorted array or a column?
Example: A1:A31 contains a list of temperatures a given month. I
would like to find the first day the temperature is below 0 degrees
What happens if there is no day in the month when the temperature
was negative? Let's say you want the value zero for the resulting
day number in this case.
This is a little messy, but it works:
o In B1, enter =A1<0 and fill it down the column to B31. This
generates TRUE for your negative values and FALSE otherwise.
o In your result cell, enter =N(MATCH(TRUE;B1:B31;0)) . The MATCH()
function searches for the first TRUE value in the column B values
and returns the relative position in the array of the first match.
(Note that this is not necessarily the row number, though will be in
your example.) This would return the #N/A error if there is no
negative temperature; the N() function makes no change to real dates
but converts this error to zero.
Alas the N() function does not works as supposed. It returns "#N/A"
if there are no numbers below zero. I have to figure out a solution.
Oh dear: sorry. It indeed appears that the behaviour of N() was
changed (between versions 3.5. and 3.6) and it no longer works as I'd
imagined. So you'll need something (even messier) such as
I am new to LibreOffice.
I do have a working program calculating meteorological statistics
written in a Pascal variant many years ago. But rewriting it in Calc 4.0
just to learn a bit about this program too.
I trust this helps.
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