At 14:42 15/10/2012 +0200, Andreas Säger wrote:
Am 15.10.2012 09:49, Pertti Rönnberg wrote:
"if value in cell c3 is /_less than_/ '1' then d3 shall be '0', else
(-- if c3 is '1' or bigger then -- ) use the integer of value in c3)"
=MIN(0;INT(C3))
This is getting sillier! This formula does not match the definition
above - and indeed for non-negative C3 is identically zero! Try
=0
instead.
Brian Barker
Privacy Policy |
Impressum (Legal Info) |
Copyright information: Unless otherwise specified, all text and images
on this website are licensed under the
Creative Commons Attribution-Share Alike 3.0 License.
This does not include the source code of LibreOffice, which is
licensed under the Mozilla Public License (
MPLv2).
"LibreOffice" and "The Document Foundation" are
registered trademarks of their corresponding registered owners or are
in actual use as trademarks in one or more countries. Their respective
logos and icons are also subject to international copyright laws. Use
thereof is explained in our
trademark policy.