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2012/7/20 Fernand Vanrie <sos@pmgroup.be>:
Op 20/07/2012 13:31, Johnny Rosenberg schreef:

2012/7/20 Fernand Vanrie<sos@pmgroup.be>:

  Johnny,
I suppose you have to run the check 2 Times, first SearchType = 0  here
we
find if there is a formula use  "."

What do you mean? Use "." as the search string? Regular expressions
set to what? True?

yep looking for not empty you need regular expressions

I did some brutal experimenting and after hundreds of swearwords (the
damned crap freeze all the time) I actually found something. Have a
look at this descriptor:

        With SearchDescriptor
                .SearchByRow=False
                .SearchRegularExpression=True
                .SearchString="^[^.]$"
                .SearchType=1 ' Search values.
        End With

First it didn't work as I expected, but it found another cell in
another column. That cell has a semi complicated formula with nested
IF's and in this case it returns F2+STYLE("Hide"). F2 in this case is
an empty cell, so now I changed the formula in the cell I wanted to
find, by just replacing the two quotes ("") with F2, and now it finds
the cell!

So "" is not good enough for making a cell empty, but I can reference
to a cell that actually is empty!

So what I need to do now, is to change all the formulas in one column,
and the search descriptor above will work, as it seems!


At least I'll try that.


Kind regards

Johnny Rosenberg
ジョニー・ローゼンバーグ


then SearchType 1 on the found area

Area? You mean what's found when setting ”search all”?

no you can define the "erea" (cells) you want to searched so when you found
that 1 cell has a formula, you need to check only this cell on a value

the SearchString has a different meaning , depending on the .SearchType
= 1 then the SearchString is the is the result of the formula or the
value
content

Okay, that's not very well designed… at least not in my opinion.

= 0 then the SearchString is the formula string

Meaning what if a cell contains only a value?

hope it helps

I don't know, will do some tests later, but it certainly feels
confusing at the moment, because when I use the Search/Replace
dialogue, it doesn't work like that at all. Selecting ”Values” in the
dialogue give me the result I want, it finds the first cell with an
empty value (in this case a cell with a formula that returns that
empty value – ""). So one question that comes to my mind is why the
LibreOffice Basic Search doesn't work the same way as the dialogue.
Maybe it's just fun to confuse the users…

As I said, I will do some more tests and come back here later.


Thanks for replying.

Kind regards

Johnny Rosenberg
ジョニー・ローゼンバーグ

Fernand

Just can't figure it out. I have a column of 2000 formulas and values.
Right now, A1:A1620 contains values, and A1621:A2000 contains
formulas. The formulas in A1621:A2000, at the moment, return empty
strings, all of them, so it looks like only the 1620 first rows
contains data.
So the formulas looks something like =IF(this and that;"";something
else) (but a bit more complicated). The point is that if I input
something on a ”new” row in one of the other columns, the A column
shall, in some cases, display something.

Okay, that's what the spreadsheet looks like, roughly.

Now I use a couple of macros to do things for me a lot faster than I
could ever do myself. One small part of a new macro I'm trying to
write needs to search for the first ”empty” row, which means the first
row where the A column contains a formula that returns an empty
string.

Here's what I tried:
Function FindCurrentRow(Sheet As Object) As Integer
         Dim SearchDescriptor As Object
         SearchDescriptor=Sheet.createSearchDescriptor()
         With SearchDescriptor
                 .SearchByRow=False ' I want to search by column,
starting
at A.
                 .SearchRegularExpression=False
                 .SearchString=""
                 .SearchType=1 ' 0=Search in formulae, 1=Search values.
         End With

         Dim Found As Object
         Found=Sheet.findFirst(SearchDescriptor)
         FindCurrentRow=Found.getCellAddress().Row
End Function

In this example I expect the function to return 1620 (which is the row
address for the cell A1621). Instead 2000 is returned, so for some
reason, when my cell formula returns "", that doesn't seem to be the
same as .SearchString="".
I also tried different values of .SearchValue, still with the same
result: 2000 instead of 1620. So it only finds the first cell in the A
column that is REALLY empty – no formula, no value.

To me this seems like a bug, but for someone else, hopefully, it might
seem like I'm just stupid, so feel free to call me stupid and, more
important, tell me what I'm doing wrong and how I should do instead…



Kind regards

Johnny Rosenberg
ジョニー・ローゼンバーグ


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