On 19 Jul 2011 at 12:26, Rich Shepard wrote:
Date sent: Tue, 19 Jul 2011 12:26:12 -0700 (PDT)
From: Rich Shepard <rshepard@appl-ecosys.com>
To: users@global.libreoffice.org
Subject: Re: [libreoffice-users] Re: New User: Three
Questions
Send reply to: users@global.libreoffice.org
On Tue, 19 Jul 2011, Andreas Säger wrote:
=X1*24 returns the time number in cell X1 in unit "Hours".
=X1*24*Y1 multiplies the hours with an hourly wage in Y1.
Andreas,
It's not working for me here. Cell D3 contains '01:00:00 PM' and cell E3
contains '07:00:00 PM'. In cell F3 I have '=(E3*24)-(D3*24)' and the display
is 0.00. If cell F3 contains '=E3-D3' then F3 shows '06:00'. The display for
1-1/4 hours is '01:15' rather than 1.25. As soon as I put parentheses around
the cells the resulting display is '0.00'. Strange.
=(E3-D3)/TIME(1,0,0)
The above formula seems to work for my test?
01:00:00 PM 07:00:00 PM 6
01:00:00 PM 04:15:00 PM 3.25
Note that with dates have two parts. The part to the left of the
decimal is the day, and the right is the time. If both dates are the
same day, there isn't a problem. One can always use the mod
function to get rid of the day portion if.
=(mod(e3,1)-mod(d3,1)) /time(1,0,0)
The division by time(1,0,0) converts the hours into a numeric
value.
Rich
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