On Mon, Jul 16, 2012 at 11:13 PM, Albert Thuswaldner
<albert.thuswaldner@gmail.com> wrote:
Sorry, It was a long time since I went to the university, but I if I'm
correct you want to calculate:
(-27)^(1/3) (note it is the same as 3x(-1)^(1/3) which to my mind
results in an complex number (not -3) thus the #VALUE!.
just to double check:
http://www.wolframalpha.com/input/?i=%28-27%29^%281%2F3%29&lk=4
Well, in fact, there're 3 roots, one of which is -3:
http://www.wolframalpha.com/input/?i=-27%3D%3Da^3
_______________________________________________
LibreOffice mailing list
LibreOffice@lists.freedesktop.org
http://lists.freedesktop.org/mailman/listinfo/libreoffice
Context
   
 
  Privacy Policy |
  
Impressum (Legal Info) |
  
Copyright information: Unless otherwise specified, all text and images
  on this website are licensed under the
  
Creative Commons Attribution-Share Alike 3.0 License.
  This does not include the source code of LibreOffice, which is
  licensed under the Mozilla Public License (
MPLv2).
  "LibreOffice" and "The Document Foundation" are
  registered trademarks of their corresponding registered owners or are
  in actual use as trademarks in one or more countries. Their respective
  logos and icons are also subject to international copyright laws. Use
  thereof is explained in our 
trademark policy.